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7r^2-32r-15=0
a = 7; b = -32; c = -15;
Δ = b2-4ac
Δ = -322-4·7·(-15)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-38}{2*7}=\frac{-6}{14} =-3/7 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+38}{2*7}=\frac{70}{14} =5 $
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